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(B) To determine the $pK_b$ order,we first determine the basicity order. Higher basicity corresponds to lower $pK_b$ values.$I$: Vinylamine $(CH_2=CH-

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$IV > II > I > III$

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(B) To determine the $pK_b$ order,we first determine the basicity order. Higher basicity corresponds to lower $pK_b$ values.$I$: Vinylamine $(CH_2=CH-NH_2)$. The lone pair on $N$ is in conjugation with the double bond,reducing its availability.$II$: $1,2,3,4$-Tetrahydroquinoline. The lone pair on $N$ is not involved in resonance with the benzene ring due to the saturated carbons,making it a relatively strong base.$III$: Pyrrolidine. It is a saturated secondary amine,making it the most basic among the given compounds.$IV$: Pyrrole. The lone pair on $N$ is involved in the aromatic sextet,making it extremely weakly basic.Basicity order: $III > II > I > IV$.Since $pK_b = -\log(K_b)$,the order of $pK_b$ is the inverse of the basicity order: $IV > I > II > III$.

Arrange the following compounds in their correct order of $pK_b$ values.

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